If the pOH of vinegar is 9.45, what is its [OH - ]?

Question

Kinsley Delacruz

Chemistry

7 January, 13:16

If the pOH of vinegar is 9.45, what is its [OH - ]?

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Answers (1)

Know the Answer?

Hugo Bishop · Answer 1

[OH⁻] = 3.54 * 10⁻¹⁰ M

Solution:

pOH is related to [OH⁻] as,

pOH = - log [OH⁻]

Putting value of pOH,

9.45 = - log [OH⁻]

Solving for [OH⁻],

[OH⁻] = 10⁻⁹·⁴⁵ ∴ 10 = Antilog

[OH⁻] = 3.54 * 10⁻¹⁰ M