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19 January, 19:04

The gas in a closed container has a pressure of 3.00 x 10² kPa 30 ° C. What will the pressure be if the temperature is lowered to - 172 ° C?

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  1. 19 January, 19:09
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    Answer: 100kPa

    Explanation:

    P1 = 3.00 x 10² kPa, P2 = ?

    T1 = 30°C = 30 + 273 = 303k

    T2 = - 172°C = - 172 + 273 = 101k

    P1/T1 = P2/T2

    3 x 10² / 303 = P2 / 101

    P2 = (3 x 10² / 303) x 101

    P2 = 100kPa
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