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1 July, 09:53

How many grams of copper metal are produced from the reaction of 21.84 ml of 0.108 m cu2 + with excess zinc metal?

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  1. 1 July, 09:56
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    The grams of copper metal that are produced from the reaction of 21.84 ml of 0.108 M cu2 + is 0.150 grams

    calculation

    Step 1 : write the equation for reaction

    Cu^2 + (aq) + Zn (s) → Cu (s) + Zn^ 2 + (aq)

    Step 2: calculate the moles of CU 2+

    moles = molarity x volume in liters

    molarity = 0.108M = 0.108 mol / l

    volume in liters = 21.84 / 1000 = 0.02184 L

    moles is therefore = 0.108 mol/l x 0.02184 L = 0.00236 moles

    Step 3 use the mole ratio to determine moles of Cu

    that is CU 2 + : Cu is 1:1 therefore the moles of CU is also = 0.00236 moles

    step 4: calculate the mass of CU

    Mass = moles x molar mass

    from periodic table the molar mass of Cu = 63.5 g / mol

    mass = 0.00236 moles x 63.5 g/mol = 0.150 grams
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