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18 June, 14:50

The equilibrium constant, Kp = 3.4 for the isomerization reaction:cis-2-butene ⇌ trans-2-butene. If a flask initially contains 0.25 atm of cis-2-butene what is the equilibrium pressure (atm) for trans-2-butene?

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  1. 18 June, 14:57
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    The equilibrium pressure of trans-2-butene is 0.193 atm.

    Explanation:

    Kp = Ptrans-2-butene/Pcis-2-butene

    Kp = 3.4

    Initial pressure of cis-2-butene = 0.25 atm

    Let the equilibrium pressure of trans-2-butene be y

    From the equation of reaction,

    Mole ratio of cis-2-butene to trans-2-butene is 1:1, therefore equilibrium pressure of cis-2-butene is (0.25 - y)

    3.4 = y / (0.25 - y)

    y = 3.4 (0.25 - y)

    y = 0.85 - 3.4y

    y + 3.4y = 0.85

    4.4y = 0.85

    y = 0.85/4.4 = 0.193 atm
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