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22 April, 17:47

suppose work input is 25 j and the output distance is 10 m factoring in the effect of friction which must be true about output force a) it equals 2.5n b) it is less than 2.5n c) it is greater than 2.5n

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  1. 22 April, 18:06
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    Therefore F ∠ 2.5N

    Explanation:

    Definition of Work:

    It is the amount of energy transferred.

    Mathematical expression:

    W = F * d

    By taking the friction into count it will define as:

    Input work = work against friction * output work

    No we will put the values:

    25 J = w + 10 m

    j = kg m²/s²

    25 kg m²/s² = w + 10 m

    when friction is exist then w > 0

    25 kg m²/s² - 10 m > 0

    15 N > 0

    Therefore F ∠ 2.5N
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