A sample of 54.0 g of methanol is heated from 25.0 °c to 35.0 °c. how much heat is required? the specific heat capacity of methanol is 2.48 j g-1 k-1.

The amount of heat required is calculated using the below formula

Q (heat) = M (mass) xC (specific heat capacity) x delta T (change in temperature)

change in the temperature in kelvin = (35+273) - (25 + 2730 = 10K

c = 2.48 j/g/k

mass = 54.0 g

Q = 54.0 g x 2.48 j/g/k x 10k = 1339.2 joules is required