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6 May, 10:12

A substance contains 35.0 g nitrogen, 5.05 g hydrogen, and 60.0 g of oxygen. how many grams of hydrogen are there in a 153-g sample of this substance

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  1. 6 May, 10:28
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    M (N) = 35.0 g

    m (H) = 5.05 g

    m (O) = 60.0 g

    m₁=153 g

    m₀=m (N) + m (H) + m (O)

    w (H) = m (H) / m₀=m (H) / [m (N) + m (H) + m (O) ]

    m₁ (H) = w (H) m₁=m₁m (H) / [m (N) + m (H) + m (O) ]

    m₁ (H) = 153*5.05/[35.0+5.05+60.0]=7.72 g

    7.72 g
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