A sealed plastic bag is filled with 1 l of air and has a pressure of 101.3 kpa. You sit on the bag and the pressure increases to 500 kpa. What is the volume of the bag as you are sitting on it? (T is constant)

The answer to your question is V2 = 0.203 kPa

Explanation:

Data

Volume 1 = V1 = 1l

Pressure 1 = P1 = 101.3 kPa

Volume 2 = V2 = ?

Pressure 2 = 500 kPa

Process

- Use the Boyle's law to solve this problem

P1V1 = P2V2

-Solve for V2

V2 = P1V1/P2

-Substitution

V2 = (101.3 x 1) / 500

-Simplification

V2 = 101.3 / 500

-Result

V2 = 0.203 kPa