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31 October, 08:02

What volume is occupied by 3.760 g of oxygen gas at a pressure of 88.4

kPa and a temperature of 19°C? Assume the oxygen is ideal. Use "8.314"

for R. Hint: Convert 3.760 g of oxygen (O2) to moles first, and remember

that temperature needs to be in Kelvin.

O 6.45 L

0.210 L

O 3.23 L

0 0,420 L

+3
Answers (1)
  1. 31 October, 08:27
    0
    3.2 L

    Explanation:

    Given dа ta:

    Mass of oxygen = 3.760 g

    Pressure of gas = 88.4 Kpa (88.4*1000 = 88400 Nm⁻²)

    Temperature = 19°C (19+273.15 = 292.15 K)

    R = 8.314 Nm K⁻¹ mol⁻¹

    Volume occupied = ?

    Solution:

    Number of moles of oxygen:

    Number of moles = mass / molar mass

    Number of moles = 3.760 g / 32 g/mol

    Number of moles = 0.12 mol

    The given problem will be solve by using general gas equation,

    PV = nRT

    P = Pressure

    V = volume

    n = number of moles

    R = general gas constant

    T = temperature in kelvin

    V = nRT/P

    V = 0.12 mol * 8.314 Nm K⁻¹ mol⁻¹ * 292.15 K / 88400 Nm⁻²

    V = 291.472 Nm / 88400 Nm⁻²

    V = 0.0032 m³

    m³ to L:

    V = 0.0032*1000 = 3.2 L
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