Mineral oil can be used in place of mercury in manometers when small pressure changes are to be measured. What is the pressure of an oxygen sample in mm of mineral oil if its pressure is 28.5 mm Hg? (d of mineral oil = 0.88 g/mL; d of Hg = 13.5 g/mL)

Question

Nash Hopkins

Chemistry

11 July, 05:25

Mineral oil can be used in place of mercury in manometers when small pressure changes are to be measured. What is the pressure of an oxygen sample in mm of mineral oil if its pressure is 28.5 mm Hg? (d of mineral oil = 0.88 g/mL; d of Hg = 13.5 g/mL)

+2

Answers (1)

Know the Answer?

Karlie Bush · Answer 1

The pressure is 473.22 mm of mineral oil

Explanation:

In manometers, the pressure can be expressed as:

Pressure = gravity * height * density

In this case, we know the height and density of mercury; and we're asked to calculate the height of oil:

Gravity * h of oil * d of oil = Gravity * h of Hg * d of Hg

h of oil * d of oil = h of Hg * d of Hg

h of oil * 0.88 g/mL = 28.5 mm Hg * 13.5 g/mL

h of oil = 437.22 mm oil