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Tia
Chemistry
27 January, 22:36
How many moles are equal to 28 grams of CaCO3
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Fatima Bell
27 January, 22:49
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N (CaCO3) = m:M
m being the mass of the sample and M being the molar mass of the compound; Molar mass is to be obtained by adding the atomic masses of all the elements in the compound.
therefore,
n (CaCO3) = m:M
=28g:100 g. mol
=0.28 mol
therefore, there are 0.28 moles in 28g of Calcium Carbonate.
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