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28 January, 04:44

Maleic acid is an organic compound composed of 41.39% C, 3.47% H, and the rest oxygen. If 0.129 mole of maleic acid has a mass of 15.0 g, what are the empirical and molecular formulas of maleic acid?

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  1. 28 January, 04:51
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    Molecular formula → C₄H₄O₄

    Empircal formula → CHO

    Explanation:

    The centesimal composition for the maleic acid is:

    41.39 g / 100 g of maleic acid → C

    3.47 g / 100 g of maleic acid → H

    100 - (41.39 + 3.47) / 100 g of maleic acid → 55.14 g / 100 g of maleic acid → O

    Let's determine the molar mass (g/mol) → 15 g / 0.129 mol = 116.2 g/mol

    So, we must do these rules of three:

    100 g of maleic acid have 41.39 g of C, 3.47 g of H and 55.14 g of O

    Therefore, 116.2 g of maleic must have:

    (116.2. 41.39) / 100 = 48 g of C

    (116.2. 3.47) / 100 = 4 g of H

    (116.2. 55.14) / 100 = 64 g of O

    We convert the mass to moles:

    48 g. 1mol / 12 g = 4 moles of C

    4 g. 1mol / 1g = 4 moles of H

    64 g. 1mol / 16 g = 4 moles of O

    Molecular formula → C₄H₄O₄

    Empircal formula → We can divide the sub-index by 4 to reach the lowest coefficients → CHO
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