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27 June, 23:32

A hydrate of sodium acetate, NaC2H3O2, has a mass of 84g. Upon dehydration 39.27g of water is extracted from the compound. What is the Formula of the compound?

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  1. 27 June, 23:48
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    First, change the 39.27grams of water to moles using the molar mass.

    Molar mass H2O = 18.02 grams/mole

    39.27 grams x (1 mole H2O / 18.02 grams) = 2.18 moles

    The mass of sodium acetate can be calculated by subtracting the mass of the compound minus the mass of water.

    84 g - 39.27 grams = 44.73 grams

    Now change does to moles using the molar mass

    Molar mass of sodium acetate = 82 g / mol

    44.73 g x (1 mole / 82 grams) = 0.545 mole

    Now divide the both value by the smallest.

    H2O - 2.18 / 0.545 = 4

    sodium acetate = 0.545 / 0.545 = 1

    The formula is NaC2H3O2 • 4 H2O
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