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23 October, 14:35

A particular first-order reaction has a rate constant of 1.35 * 102 s-1 at 25.0°c. what is the magnitude of k at 75.0°c if ea = 85.6 kj/mol?

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  1. 23 October, 16:12
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    According to this formula:

    K = A * (e^ (-Ea/RT) when we have K = 1.35X10^2 & T = 25+273 = 298K &R=0.0821

    Ea = 85.6 KJ/mol So by subsitution we can get A:

    1.35x10^2 = A * (e^ (-85.6/0.0821*298))

    1.35x10^2 = A * 0.03

    A = 4333

    by substitution with the new value of T (75+273) = 348K & A to get the new K

    ∴K = 4333 * (e^ (-85.6/0.0821*348)

    = 2.16 x10^2
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