Express the equilibrium constant for the following reaction. P (g) + 3/2 Cl2 (g) ↔ PCl3 (g) K = [PCl3]^2/[P]^2[Cl2]^3K = [PCl3]/[P][Cl2]^3/2K = [P][Cl2]^3/2/[PCl3]K = [P]^1/2[Cl2]^1/3/[PCl3]^1/2K = [PCl3]^2/[P]2[Cl2]3

Question

Briana Figueroa

Chemistry

12 June, 00:32

Express the equilibrium constant for the following reaction. P (g) + 3/2 Cl2 (g) ↔ PCl3 (g) K = [PCl3]^2/[P]^2[Cl2]^3K = [PCl3]/[P][Cl2]^3/2K = [P][Cl2]^3/2/[PCl3]K = [P]^1/2[Cl2]^1/3/[PCl3]^1/2K = [PCl3]^2/[P]2[Cl2]3

+2

Answers (2)

Know the Answer?

Devin Lamb · Answer 1

b) K = [PCl3] / [P][Cl2]∧ (3/2)

Explanation:

P (g) + 3/2 Cl2 (g) ↔ PCl3 (g)

equlibrium constant (K):

⇒ K = [PCl3] / [P].[Cl2]∧ (3/2)

Natalie Hodge · Answer 2

K = [PCl3]/[Cl2]^3/2[P]

Explanation:

To get an expression for the equilibrium constant, we simply place the concentrations of both the reactants and the product in terms of square bracket and raise them to the power of their coefficients in the balanced equations.

After doing this we place the expression of the product over that of the reactant.

K = [PCl3]/[Cl2]^3/2[P]