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8 April, 20:33

In the laboratory you dissolve 24.6 g of calcium acetate in a volumetric flask and add water to a total of 250 ml. What is the M of the solution? The concentration of calcium cation? Concentration of acetate anion

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  1. 8 April, 20:36
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    Ca (C2H3O2) 2

    mole of calcium acetate = 24.6 / (40.1 + (2 * (2*12+3*1+2*16)))

    =0.156 mol

    molarity = mole / volume = 0.156 / ((250cm^3/1000) dm^3) = 0.624M
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