Find q when 22.0g of water is heated from 17.0 degrees Celsius to 100 degrees Celsius

When 22.0 g of water is heated from 17 °C to 100 °C what amount of heat absorbed?

When 22.0 g of water is heated from 17 °C to 100 °C water absorbed 7643.64 j heat.

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m. c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Given dа ta:

Mass of water = 22.0 g

Initial temperature = 17°C

Final temperature = 100°C

Solution:

ΔT = T₂ - T₁

ΔT = 100°C - 17 °C = 83°C

Q = m. c. ΔT

Q = 22 g * 4.186 j/g °C * 83 °C

Q = 7643.64 j

It means water require more heat which is 7643.64 j to increase its temperature from 17 °C to 100 °C.