Read the chemical equation.

N2 + 3H2 → 2NH3

Using the volume ratio, determine how many liters of NH3 is produced if 3.6 liters of H2 reacts with an excess of N2, if all measurements are taken at the same temperature and pressure?

5.4 liters

2.4 liters

1.8 liters

1.2 liters

the balanced equation for the reaction is

N₂ + 3H₂ - -> 2NH₃

since number of moles of gas is directly proportional to volume of gas once all other parameters are kept constant

the volume ratio of reactant gases is equal to molar ratio

therefore volume ratio of H₂ to NH₃ is 3:2

so 3 L of H₂ reacts to produce 2 L of NH₃ assuming N₂ is in excess

when 3.6 L of H₂ reacts - 2/3 x 3.6 L = 2.4 L of N₂ is formed

So 2.4 L of NH₃ is produced

2.4 L is the correct answer

Explanation:

volume ratio = 2NH3/3H2

3.6*2/3=2.4 L

I this isn't clear enough the other person has a really good explanation.