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16 April, 16:26

Molarity of 82.6 g sucrose, C12H22O11, in 725 mL

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  1. 16 April, 16:35
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    0.33 M

    Explanation:

    Given dа ta:

    Mass of sucrose = 82.6 g

    Volume = 725 mL

    Molarity = ?

    Solution:

    725/1000 = 0.725 L

    Molarity = number of moles of solute / volume in litter

    Number of moles of sucrose:

    Number of moles = mass/molar mass

    Number of moles = 82.6 g / 342.3 g/mol

    Number of moles = 0.24 mol

    Molarity = number of moles of solute / volume in litter

    Molarity = 0.24 mol / 0.725 L

    Molarity = 0.33 M
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