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18 October, 19:17

a gaseous mixture of O2 and N2 has 22.8% of the pressure exerted by N2. What is the partial pressure of oxygen in the mixture, if the total pressure is 785.0 mmHg?

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  1. 18 October, 19:41
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    The partial pressure of oyxgen O2 is 606 mmHg

    Explanation:

    Step 1: Data given

    Percentage N2 = 22.8 %

    The total pressure = 785.0 mmHg

    Step 2: Calculate partial pressures

    Partial pressure = percentage * total pressure

    Partial pressure N2 = 0.228 * 785.0 mmHg

    Partial pressure N2 = 179 mmHg

    Step 3: Calculate partial pressure O2

    Partial pressure O2 = 785.0 mmHg - 179.0 mmHg

    Partial pressure O2 = 606 mmHg

    OR (1 - 0.228) * 785.0 = 606 mmHg

    The partial pressure of oyxgen O2 is 606 mmHg
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