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4 April, 23:09

The density of a metal is 10.5 g/cm3. If the mass of themetal

is 5.25 g and it is placed in 11.2 ml of water, how much willthe

water rise?

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Answers (1)
  1. 4 April, 23:27
    0
    11.7 mL

    Explanation:

    Density of a substance is given by the mass of the substance divided by the volume of the substance.

    Hence, d = m / V

    V = volume

    m = mass,

    d = density,

    From the question,

    The density of the metal = 10.5 g/cm³

    The mass of the metal = 5.25 g

    Hence, the volume can be calculated from the above formula, i. e.,

    d = m / V

    V = m / d

    V = 5.25 g / 10.5 g/cm³

    V = 0.5 cm³

    Since, The unit 1 mL = 1 cm³

    V = 0.5 mL

    The vessel has 11.2 mL of water,

    The new volume becomes,

    11.2 mL + 0.5 mL = 11.7 mL
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