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4 April, 22:15

What celsius temperature, t2, is required to change the volume of the gas sample in part a (t1 = 43 ∘c, v1 = 1.13*103 l) to a volume of 2.26*103 l? assume no change in pressure or the amount of gas in the balloon?

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  1. 4 April, 22:32
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    In this case, you are given the temperature and volume of the gas. To answer this question, you will need to use PV=nRT formula. Since the number of molecule and pressure is not changed then you can put 1 in both equations. The formula will become:

    PV=nRT

    1 V = 1 T

    V=T

    T/V = 1

    Dont forget that the celcius unit should be converted into kelvin. Then the calculation to find the temperature would be:

    T1/V1 = T2/V2

    (43+273) / 1.13x10^3 = T2 / 2.26 x 10^3

    T2 = (2.26 * 10^3) / (1.13 * 10^3) * (43+273)

    T2 = 2 * 316 = 632° K = 359°C
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