If 8 moles of FeCl₃ react with 8 moles of O₂ what is the limiting reactant?

4Fecl3 + 3O2 (arrow) 2Fe2O3 + 3Cl2

FeCl3

Explanation:

We'll begin by writing the balanced equation for the reaction. This is shown below:

4FeCl3 + 3O2 - > 2Fe2O3 + 6Cl2

Thus, the limiting reactant can be obtained as follow:

From the balanced equation above,

4 moles of FeCl3 reacted with 3 moles of O2.

Therefore, 8 moles of FeCl3 will react with = (8 x 3) / 4 = 6 moles of O2.

From the calculation made above, we can see that a lesser amount of O2 is needed to react completely with 8 moles of FeCl3. Therefore, FeCl3 is the limiting reactant.