If I make a solution by adding 83grams of sodium hydroxide to 750mL I'd water what is the molarity of sodium hydroxide

2.8 mol·L⁻¹

Step-by-step explanation:

1. Convert grams to moles.

Moles NaOH = 83 g NaOH * (1 mol NaOH / 40.00 g NaOH)

= 2.08 mol NaOH

2. Convert millilitres to litres

V = 750 mL * (1 L/1000 mL)

= 0.7500 L

3. Calculate the molar concentration (c)

c = moles/litres = 2.08 mol/0.7500 L

= 2.8 mol/L