Ammonia gas is dissolved in a 1.00 * 10-4M solution of CuSO4to give an equilibrium concentration of [NH3] = 1.60 * 10-3M. Calculate the equilibrium concentration of Cu2 + (aq) ions in the solution

Mixing Ammonia gas into a solution of Copper (II) Sulfate will give Ammonium Sulfate and a precipitate of Copper (II) Hydroxide (Cu (OH) ₂). The Ksp of Cu (OH) ₂ is published = > 2.2 x 10⁻²². Such gives a solubility * of the Cu (OH) ₂ to be ~1.77 x 10⁻⁷M = > [Cu⁺²] ~1.77 x 10⁻⁷M and [OH⁻] = 2 (1.77 x 10⁻⁷) M = 3.53 x 10⁻⁷M. The reaction of Ammonium Hydroxide and Copper (II) Sulfate will generate 1 x 10⁻⁴ mole Cu (OH) ₂ as a precipitate but only 1.77 x 10⁻⁷ mole of the hydroxide will remain in 1 Liter of solution b/c of extreme limited solubility.

*Solubility of 1:2 ionization ratio salts = CubeRt (Ksp/4).