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19 July, 04:19

Examine the reaction C 3 H 8 + 5O2->3CO 2 + 4H 2 O. If the reaction starts with 2.5g C 3 H 8 what is the theoretical yield of water? If the reactant yields 75 % of the theoretical yield of water, how many grams of water were produced?

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  1. 19 July, 04:21
    0
    Theoretical yield = 4.09 g water.

    75% yield = 3.07g water.

    Explanation:

    C3H8 + 5O2 - --> 3CO2 + 4H2O

    Using atomic masses:

    (12 * 3 + 8 * 1.008) g C3H8 yield (theoretically) (4 * (2*1.008 + 16) g water

    44.06g C3H8 yields 72.06g water

    So 2.5 g yields (72.06/44.06) * 2.5

    = 4.09 g water.

    If the yield is 75% then it is 4.09 * 0.75

    = 3.07 g water.
  2. 19 July, 04:22
    0
    If I correct, answer is C, 75%.
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