Find the concentration of H + ions at a pH = 11 and pH = 6. Then divide the concentration of H + ions at a pH = 11 by the of H + ions at a pH = 6. Record your answer in Table C. What is the concentration of H + ions at a pH = 11? mol/L What is the concentration of H + ions at a pH = 6? mol/L How many fewer H + ions are there in a solution at a pH = 11 than in a solution at a pH = 6?

The hydrogen ion concentration can be calculated using pH

pH = - log [H⁺]

when pH is known antilog of pH needs to be calculated

[H⁺] = antilog (-pH)

when pH = 11

[H⁺] = antilog (-11)

[H⁺] = 1 x 10⁻¹¹ mol/L

when pH = 6

[H⁺] = antilog (-6)

[H⁺] = 1 x 10⁻⁶ mol/L

then to find how much fewer H⁺ ions at pH = 11 than when pH = 6, we have to find the ratio.

ratio = (1 x 10⁻¹¹ mol/L) / (1 x 10⁻⁶ mol/L)

there's 10⁻⁵ lesser H⁺ ions when pH - 11 than when pH - 6

0.00000000001

0.000001

100,000