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2 November, 07:50

Suppose you had 10 mol of NaCl and you dissolved it in exactly 3.00 kg of pure water (the solvent). What would be the molality of the solution in mol/kg?

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  1. 2 November, 08:01
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    Molality = number of moles of solute/mass of solvent in kg = 10/3 = 3.34 mol/kg.
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