0 ml of a 1.20 m solution is diluted to a total volume of 228 ml. a 114-ml portion of that solution is diluted by adding 111 ml of water. what is the final concentration? assume the volumes are additive.

54.0 ml of a 1.2 m solution was diluted to a total volume of 228 ml

USing dilution equation

M1V1 = M2V2

Where M1V1 is before dilution while M2V2 is after dilution.

Therefore;

M1 = 1.20 M, V2 = 54 ml,

M2 = V2 = 228 ml

1.20 M * 54 ml = M2 * 228 ml

M2 = (1.2 * 54) / 228 ml

= 0.2842 M

0.2842 * 114 ml = M2 * (114 + 111)

M2 = (0.2842 * 114) / 225

= 0.143995

= 0.144 M