A 5.0 gallon container contains 15.0 moles of propane gas at room temperature (20. °c). what is the pressure of the gas? (1.0 gal = 3.79 l)

Question

Elena Roberson

Chemistry

20 January, 20:04

A 5.0 gallon container contains 15.0 moles of propane gas at room temperature (20. °c). what is the pressure of the gas? (1.0 gal = 3.79 l)

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Answers (1)

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Alina Little · Answer 1

We apply the ideal gas equation:

PV = nRT

V = 5 x 3.79/1000 m³

= 0.01895

T = 20 + 273 = 293 K

n = 15

R = 8.314

P = nRT/V

= (15 x 8.314 x 293) / (0.01895)

= 1,928,234 Pa ≈ 1.93 MPa