A tank of oxygen has a volume of 1650 L. The temperature of the gas inside is 35? C. If there are 9750 moles of oxygen in the tank what is the pressure in psi?

2192.64 PSI.

Explanation:

From the general law of ideal gases:

PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the container in L (V = 1650 L).

n is the no. of moles of the gas in mol (n = 9750 mol).

R is the general gas constant (R = 0.082 L. atm/mol. K).

T is the temperature of the gas in (T = 35°C + 273 = 308 K).

∴ P = nRT/V = (9750 mol) (0.082 L. atm/mol. K) (308 K) / (1650 L) = 149.2 atm.

To convert from atm to PSI:

1 atm = 14.696 PSI.

∴ P = 149.2 atm x (14.696 PSI/1.0 atm) = 2192.64 PSI.