A 1.205 g sample mixture of lithium hydrogen carbonate is decomposed by heating. If they mass loss is 0.275g, what is the percentage of LiHCO3 in the unknown mixture?

Question

Carsen Gardner

Chemistry

4 July, 17:12

A 1.205 g sample mixture of lithium hydrogen carbonate is decomposed by heating. If they mass loss is 0.275g, what is the percentage of LiHCO3 in the unknown mixture?

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Rohan Reed · Answer 1

To determine the percent of LiHCO3 in the mixture, we need to calculate for the amount of LiHCO3 by first knowing what really happens in the process. We do as follows:

2 LiHCO3 (s) - - Heat - - > Li2CO3 (s) + H2CO3 (g)

0.275 g = mass of H2CO3

mass of LiHCO3 = 0.275g (1 mol / 62.03 g) (2 mol LiHCO3 / 1 mol H2CO3) (67.96 g / 1 mol) = 0.6026 g LiHCO3

% percent = 0.6026 / 1.205 x 100 = 50%