How many grams of water can be produced when 65.5 grams of sodium hydroxide reacts with excess sulfuric acid? Unbalanced equation: H2SO4 + NaOH → H2O + Na2SO4 Show all work to get final answer.

Question

Nicholas Becker

Chemistry

25 August, 03:05

How many grams of water can be produced when 65.5 grams of sodium hydroxide reacts with excess sulfuric acid? Unbalanced equation: H2SO4 + NaOH → H2O + Na2SO4 Show all work to get final answer.

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Eleanor Wiley · Answer 1

The balanced reaction that describes the reaction between sulfuric and sodium hydroxide to produce sodium sulfate and water is expressed H2SO4 + 2NaOH → 2H2O + Na2SO4. When 65.5 grams of sodium hydroxide reacts with excess sulfur, we need first to convert the mass to moles and multiply by stoich ratio 2/2 or 1. Hence the moles is multiplied to the molar mass of water. The final answer is 29.475 grams water.