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17 February, 07:58

Extra Stoichiometry Practice

1. How many grams of aluminum oxide can be formed by the reaction of 38.8 g of aluminum with

oxygen?

4 Al (8) + 3 O2 (g) →2 A12O (s)

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Answers (1)
  1. 17 February, 08:20
    0
    Answer: 50. 4g

    Explanation:

    First calculate number of moles of aluminium in 38.8g

    Moles = 38.8g / 26.982mol/g

    = 1.44mol

    By looking at the balance equation you can see that 4 moles of aluminium produce 2 moles of aluminium oxide.

    4 = 2

    1.4 = x

    Find the value of x

    x = (1.4*2) / 4 = 0.72 mol

    0.72 moles of aluminium oxide are produced from 38.8g of aluminium

    Now find the mass of aluminium produced.

    Mass = moles * molar mass

    = 0.72mol * 69.93 mol/g

    = 50.4g
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