Ammonia forms when hydrogen gas reacts with nitrogen gas according to the equation below. If equal moles of nitrogen and hydrogen are combined, the maximum number of moles of ammonia that could be formed will be equal to:two thirds the number of moles of hydrogenthe number of moles of hydrogenthe number of moles of nitrogentwice the number of moles of nitrogen

The number of moles NH3 produced is two thirds of moles of hydrogen.

Explanation:

Step 1: Data given

Number of moles H2 = Number of moles N2

Step 2: The balanced equation

3H2 + N2 → 2NH3

Step 3: Calculate mol NH3 produced

For 1 mol N2 consumed, we need 3 moles of H2, to produce 2 mol of NH3

H2 is the limiting reactant. This will be completely consumed.

N2 is in excess. There will be consumed 1/3 of moles of H2

The mole ratio H2:NH3 = 3:2

The number of moles NH3 produced is two thirds of moles hydrogen.

The number of moles N2 is one third of moles hydrogen.

Two thirds the number of moles of hydrogen

Explanation:

The balanced reaction is

3H₂ + N₂ → 2NH₃

So 1 mol of nitrogen gas reacts completely with 3 moles of hydrogen gas, to produce 2 moles of ammonia.

If equal moles of nitrogen and hydrogen are combined, then hydrogen would be the limiting reactant. Let's say we have 3 moles of each reactant, one mol of N₂ reacts with the 3 moles of H₂ and produces 2 moles of NH₃, and 2 moles of N₂ would remain. So the answer is two thirds the number of moles of hydrogen.