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7 November, 08:40

N aqueous solution of sodium hydroxide is standardized by titration with a 0.154 m solution of hydrochloric acid. if 17.5 ml of base are required to neutralize 17.6 ml of the acid, what is the molarity of the sodium hydroxide solution?

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  1. 7 November, 08:45
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    The balanced equation for the above reaction is as follows;

    NaOH + HCl - - > NaCl + H₂O

    stoichiometry of NaOH to HCl is 1:1

    Number of HCl moles reacted - 0.154 mol/L x 0.0176 L = 0.00271 mol

    the number of NaOH moles reacted = number of HCl moles reacted

    number of NaOH moles reacted - 0.00271 mol

    number of NaOH moles in 17.5 mL - 0.00271 mol

    therefore NaOH moles in 1000 mL - 0.00271 mol / 17.5 mL x 1000 mL

    molarity of NaOH - 0.155 M
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