Consider the positions of barium (Ba), sulfur (S), silicon (Si), and calcium (Ca) on the periodic table. The atoms of which element require the least amount of energy to give up an electron when forming chemical bonds?

Question

Maleah

Chemistry

7 November, 08:14

Consider the positions of barium (Ba), sulfur (S), silicon (Si), and calcium (Ca) on the periodic table. The atoms of which element require the least amount of energy to give up an electron when forming chemical bonds?

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Averi Marsh · Answer 1

Element atomic number position

Ba 56 group 2, period 6

Ca 12 group 2, period 3

S 16 group 16, period 3

Si '14 group 14, period 3

Now, you need to know the properties of the different type of elements and the tendencies on the periodic table.

The metallic elements are, those placed on the left side of the periodic table, are the ones that release an electron more easily, so they will requiere less energy to give it up when forming chemical bonds.

The higher the metallic character the less the energy need to give up an electron.

The metallic character grows as the group number decreases (goes to the left) period increases (goes downward), so among the elements considered, Barium will require the least amount of energy to give un an electron when forming chemical bonds.