Calculate the pH of a solution in which [H3O+]=9.5*10-9M. Express the pH of the solution to two decimal places.

When Ph = - ㏒[H+] and when we have [H+] represents by [H3O+] = 9.5x10^-9 M

as the Ph is equal the negative ㏒ of the concentration of H + ions or H3O + hydronium ions.

So, by substitution in Ph equation:

∴ Ph = - ㏒ (9.5x10^-9)

= 8.02