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1 February, 06:23

If 200. mL of 0.60 M MgCl2 (aq) is added to 400 mL of distilled water, what is the concentration of Mg and Cl in the resulting solution?

A. 0.20 M Mg ion & 0.20 M Cl ionB. 0.40 M Mg ion & 0.40 M Cl ionC. 0.20 M Mg ion & 0.40 M Cl ionD. 2.0 M Mg ion & 2.5 M Cl ion

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  1. 1 February, 06:32
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    C. 0.20 M Mg ion & 0.40 M Cl ion

    Explanation:

    MgCl₂ is a ionic salt which is dissociated as this

    MgCl₂ → Mg²⁺ + 2Cl⁻

    First of all, we have a solution of 200 mL, with [MgCl₂] = 0.6M

    Molarity. volume = moles.

    0.6 mol/l. 0.2l = 0.12 mol

    MgCl₂ → Mg²⁺ + 2Cl⁻

    0.12mol 0.12 0.24

    This moles are also in 400mL of water, so the new concentration is

    [Mg²⁺] = 0.12 m/0.6L = 0.2M

    [Cl⁻] = 0.24 m/0.6L = 0.4M

    Remember we initially have 200mL and then, we add 400 mL, so we supose aditive volume. (600mL)
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