1. The combustion of ethene, C2H4, is an exothermic reaction. Use the information below to

determine the amount of energy given off when 2.3 moles of ethene is combusted.

C2H4 + 3 02 02 CO2 + H2O

AH = - 1390 kJ

-3197 kj

Explanation:

Chemical equation:

C₂H₄ + O₂ → CO₂ + H₂O ΔH = - 1390 KJ

Balanced chemical equation:

C₂H₄ + 3O₂ → 2CO₂ + 2H₂O ΔH = - 1390 KJ

It can be seen in equation that one mole of C₂H₄ react with 3 mole of oxygen and produced 1390 kj energy.

When 2.3 moles C₂H₄ react the energy produced is,

1 mole = - 1390 KJ

2.3 mol * - 1390 KJ / 1mol = - 3197 kj

The given reaction is combustion reaction of hydrocarbon. when hydrocarbons burn in the presence of oxygen carbon dioxide and water are produced.

In given reaction 1 mole of ethylene react with 3 moles of oxygen and produced 2 moles of CO₂ and 2 moles of water.