8.0g of NaOH was dissolved in 200ml of water to prepare a solution was used to titrate a 30 ml sample of H SO a. (Spts) Write the chemical equation s) for the dissociation of H SO, in water b. (5pts) Write a net ionic equation of the reaction between NaOH and H, SO c (5pts) If 20 ml of the NaOH solution is used to titrate the sample, what is the molarity of H, SO? d. (5pts) If 2.5 M NaOH solution was used to prepare the solution instead of solid NaOH how many liters of 2.5M NaOH solution is needed to prepare the solution? e. (5pts) If0.15M Mg (OH), solution was used to titrate the sample instead, how many milliliters of Mg (OH) 2 solution would be required to titrate the sample?

Question

Giuliana Ritter

Chemistry

22 April, 14:00

8.0g of NaOH was dissolved in 200ml of water to prepare a solution was used to titrate a 30 ml sample of H SO a. (Spts) Write the chemical equation s) for the dissociation of H SO, in water b. (5pts) Write a net ionic equation of the reaction between NaOH and H, SO c (5pts) If 20 ml of the NaOH solution is used to titrate the sample, what is the molarity of H, SO? d. (5pts) If 2.5 M NaOH solution was used to prepare the solution instead of solid NaOH how many liters of 2.5M NaOH solution is needed to prepare the solution? e. (5pts) If0.15M Mg (OH), solution was used to titrate the sample instead, how many milliliters of Mg (OH) 2 solution would be required to titrate the sample?

+3

Answers (1)

Know the Answer?

Kale Huff · Answer 1

Explanation

molecular weight of NaOH = 40 G

8g = 8 / 40 = 0.2 mol

molarity of solution =.2 x 1000/200 = 1 M.

a) H₂SO₄ = 2H⁺ + SO₄⁻²

b) 2NaOH + H₂SO₄ = Na₂SO₄ + 2H₂O.

c)

S₁V₁ = S₂ V₂ = S₂ = S₁V₁/V₂ = 1M X 20 / 30 = 2/3M.

d) S₁V₁ = S₂V₂ = 2.5M X V = 1 M X 200, V = 200/2.5 = 80 mL =.08 L.

e).15 M X V = 1M X 200, V = 200/.15 = 1333.33 mL