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11 January, 17:13

In one process, 5.95 kg of caf2 is treated with an excess of h2so4 and yields 2.45 kg of hf. calculate the percent yield of hf.

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  1. 11 January, 17:20
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    Answer is: yield of reaction is 80,3%.

    Chemical reaction: CaF₂ + H₂SO₄ → CaSO₄ + 2HF.

    m (CaF₂) = 5,95 kg · 1000 g/kg = 5950 g.

    n (CaF₂) = m (CaF₂) : M (CaF₂).

    n (CaF₂) = 5950 g : 78 g/mol.

    n (CaF₂) = 76,28 mol.

    From chemical reaction: n (CaF₂) : n (HF) = 1 : 2.

    n (HF) = 76,28 mol · 2 = 152,56 mol.

    m (HF) = 152,56 mol · 20 g/mol.

    m (HF) = 3051,2 g : 1000 g/kg = 3,0512 kg.

    yield = 2,45 kg kg : 3,0512 kg · 100% = 80,3%.
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