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2 August, 22:28

If a person burns 2171 Cal each day, how much energy (kJ) does she burn in 2 days?

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  1. 2 August, 22:33
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    As 1 calorie = 4.184 jouls

    Or

    1 calorie = 0.004184 kilojouls

    Total calories for two days = 2171 x 2 = 4342 calories

    Hence the energy in kj = 4342 x 0.004184 = 18.16 kj
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