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2 August, 22:29

By what factor will the rate of the reaction change if the ph decreases from 6.00 to 2.00? express your answer numerically using two significant figures. view available hint (s)

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  1. 2 August, 22:46
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    The reaction equation is first order with respect to [H+]

    when PH1 = - ㏒[H+]1 so, when PH = 6

    So by substitution:

    ∴ 6 = - ㏒[H+]1

    ∴[H+]1 = 1 x 10^-6

    and when PH2 = - ㏒[H+]2 so, when PH2 = 2

    so by substitution:

    ∴ 2 = - ㏒[H]2

    ∴[H]2 = 1 x 10^-2

    So the rate of reaction changes by the factor of:

    [H2]2/[H]1 = (1 x 10^-2) / (1 x 10^-6) = 10000

    It is 10000 times faster when PH decreases from 6 to 2
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