A mixture of sand (SiO2), sodium chloride (NaCl), and iron (Fe) filings had a mass of 30.126 g. After analysis this mixture was found to contain 15.976 g of sand and 3.455 g of iron. What is the mass percent (%) of sodium chloride in the sample?

Question

Rodolfo

Chemistry

24 April, 09:20

A mixture of sand (SiO2), sodium chloride (NaCl), and iron (Fe) filings had a mass of 30.126 g. After analysis this mixture was found to contain 15.976 g of sand and 3.455 g of iron. What is the mass percent (%) of sodium chloride in the sample?

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Answers (1)

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Winston Kaufman · Answer 1

35.5 % NaCl

Explanation:

Total mass of mixture = 30.126 g

Mass of sand = 15.976 g

Mass of iron = 3.455 g

Mass of NaCl = ? → Total mass - 15.976 g - 3.455 g = 10.695 g

% mass of NaCl in the sample → (Mass of NaCl / Total mass). 100

(10.695 g / 30.126 g). 100 = 35.5 %