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23 September, 03:30

at constant atmospheric pressure, the temperature of a gas that occupies the volume of 5.30 L is 298 K. what is the temperature of the gas if it is allowed to expand to 7.60 L?

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  1. 23 September, 03:56
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    The new temperature of the gas is 427K

    Explanation:

    In this case we use Charles's Law according to which the volume and temperature of a certain amount of gas are related, keeping the pressure constant.

    V1 / T1 = V2 / T2

    5,30L/298K=7,60L/T2

    T2=7,60L / (5,30L/298K) = 427,32K
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