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20 September, 13:51

If the solubility of o2 at 0.370 atm and 25 °c is 15.3 g/100 g h2o, what is the solubility of o2 at a pressure of 2.40 atm and 25 °c?

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  1. 20 September, 14:20
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    According to Henry's law:

    C = K P when,

    C is the solubility of a gas at a constant temperature in a particular solvent.

    K is the Henry law constant

    p is the pressure of the gas

    we have the pressure and the solubility so we will get the K at first:

    by substitution:

    0.153 = K * 0.37atm

    K = 0.4

    ∴ C when P = 2.4 atm

    ∴ C = 0.37 * 2.4 atm = 0.888 = 88.8 g/100g H2O
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