What is the molality of a solution that contains 5 moles of solute in 100 kilograms of water?

molality = (moles of solute) / (kilogram of solvent)

moles of solute = (75.2 g AgClO4) / (mole mass AgClO4)

moles of solute = (75.2 g AgClO4) / (207.3206 g/mol)

moles of solute = 0.3627232 mol

molality = (0.3627232 mol) / (0.0752 Kg)

molality = 4.8234468 m or 4.82 m rounded to three significant figures