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1 November, 20:53

What volume of 0.225 m k3po4 solution is necessary to completely react with 134 ml of 0.0112 m nicl2?

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  1. 1 November, 21:04
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    To answer this question, you need to know the equation for the reaction. The equation should look like this:

    2K3PO4 (aq) + 3NiCl2 (aq) - - > Ni3 (PO4) 2 (s) + 6KCl (aq)

    In the equation, 2 K3PO4 would react with 3 NiCl2. Then the calculation should be look like this:

    V2 = V1*m1/m2 * 2/3

    V2 = 134ml * 0.0112 / 0.225 * 2/3

    V2 = 4.46ml
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