Ask Question
10 April, 12:49

If 119.5 g of iron is mixed with 279.50 g of copper (II) nitrate, what is the limiting reagent for the reaction?

+3
Answers (1)
  1. 10 April, 13:08
    0
    Copper ii nitrate is the limiting reagent

    Explanation:

    The first thing to write here is the equation of reaction;

    Fe + Cu (NO3) 2 - -> Fe (NO3) 2 + Cu

    When we talk of limiting reagent, we mean the reactant that is totally consumed upon the completion of the chemical reaction

    To get the limiting reagent, we can know this by calculating the mass of a specific product formed from each of the masses of the reactants

    Now, we can use the amount of copper solid deposited by each of the reactants to know the limiting reagent here.

    Since the mole ratio in all cases is 1 to 1, this will be easy

    For the iron, the number of moles reacted is mass of iron / atomic mass of iron

    That would be 119.5/56 = 2.134 moles

    Now since the mole ratio is 1 to 1, 2.134 moles of copper will be formed

    Thus, the mass of copper produced from the iron will be number of moles * atomic mass of copper = 2.134 * 64 = 136.57g

    Now from the nitrate, the number of moles is

    mass mixed / molar mass of copper nitrate

    molar mass of copper nitrate is 188g/mol

    number of moles is thus 279.5/188 = 1.487 moles

    Since the mole ratio is 1 to 1, it means that the number of moles of copper produced too is 1.487 moles

    The mass of copper produced from this is number of moles of copper * atomic mass of copper

    That will be 1.487 * 64 = 95.15g

    Now, since the copper nitrate produces less amount of copper solid, it is the the reagent to be consumed first and thus it is our limiting reagent
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “If 119.5 g of iron is mixed with 279.50 g of copper (II) nitrate, what is the limiting reagent for the reaction? ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers